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Your mistake is that for write-write A will not construct a PI, but will send the current block. This current image will of course have the uncommitted changes, and the necessary row lock ITL information.
Thank you for your reply. I am still confused with the concept.
The Node A send the current block to the instance that sends requests and node A also preserve the PI of the block sent to the node B.So here after sending the block to node B, if node A commits the changes it made, how the changes will be recorded in the block.
The changes are already in the block. The ITL will be cleared eventually by the delayed block clean-out mechanism.
Thank you very much ! i am now comfortable about the concept.