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1. Re: Identifying Coordinate Positions in a Polygon
NoelKhan May 13, 2013 11:41 AM (in response to user154136)Robert,
Yes, that functionality already exists. You can write a SELECT statement using these function to get, for example, the bottomleft and upperright.
[ SDO_GEOM.SDO_MIN_MBR_ORDINATE  http://docs.oracle.com/cd/B19306_01/appdev.102/b14255/sdo_objgeom.htm#i866250 ]
[ SDO_GEOM.SDO_MAX_MBR_ORDINATE  http://docs.oracle.com/cd/B19306_01/appdev.102/b14255/sdo_objgeom.htm#i866249 ]
Regards,WITH SampleGeometry AS ( SELECT SDO_GEOMETRY( 'POLYGON ((6091829.946 2271465.64, 6092444.797 2271460.591, 6092445.067 2271797.663, 6091825.777 2271802.748, 6091829.946 2271465.64))', 40986 ) geometry FROM dual ) SELECT SDO_GEOM.SDO_MIN_MBR_ORDINATE(geometry,1) As left, SDO_GEOM.SDO_MIN_MBR_ORDINATE(geometry,2) As bottom, SDO_GEOM.SDO_MAX_MBR_ORDINATE(geometry,1) As right, SDO_GEOM.SDO_MAX_MBR_ORDINATE(geometry,2) As upper FROM SampleGeometry;  "Results" LEFT BOTTOM RIGHT UPPER     6091825.78 2271460.59 6092445.07 2271802.75
Noel 
2. Re: Identifying Coordinate Positions in a Polygon
user154136 May 13, 2013 12:09 PM (in response to NoelKhan)Thanks Noel, I am aware of these functions for MBRs. In my case the geometry is not a rectangle, so this will not work. This will give me the coordinates of the bounding rectangle instead of the coordinates of the polygon itself. This can be quite different values depending on the shape of the polygon.
Thanks
Robert 
3. Re: Identifying Coordinate Positions in a Polygon
user154136 May 13, 2013 12:11 PM (in response to NoelKhan)Dup Post
Edited by: user12191713 on May 13, 2013 10:11 AM 
4. Re: Identifying Coordinate Positions in a Polygon
NoelKhan May 13, 2013 1:18 PM (in response to user154136)Robert,
The question did seem familiar. Anyhow, I understand the problem a little better.
If you want to find the O's, you could search for the intersection between your polygon and linesdefiningtheMBR. The following example demonstrates how you can identify the left and right most points of your polygon (not the enclosing MBR). "MBR's points are Xs" . O X  * *  * *  * *  * *  O O  * *  * *  * *  * * XO 
Here's an alternative that doesn't generate intermediate lines:WITH SampleGeometry AS ( SELECT SDO_GEOMETRY( 'POLYGON ((6091829.946 2271465.64, 6092444.797 2271460.591, 6092445.067 2271797.663, 6091825.777 2271802.748, 6091829.946 2271465.64))', 40986 ) geometry FROM dual ), MbrEdges AS ( SELECT SDO_GEOMETRY('LINESTRING (' SDO_GEOM.SDO_MIN_MBR_ORDINATE(geometry,1)' ' SDO_GEOM.SDO_MIN_MBR_ORDINATE(geometry,2)',' SDO_GEOM.SDO_MIN_MBR_ORDINATE(geometry,1)' ' SDO_GEOM.SDO_MAX_MBR_ORDINATE(geometry,2)')', 40986 ) LeftEdge, SDO_GEOMETRY('LINESTRING (' SDO_GEOM.SDO_MAX_MBR_ORDINATE(geometry,1)' ' SDO_GEOM.SDO_MIN_MBR_ORDINATE(geometry,2)',' SDO_GEOM.SDO_MAX_MBR_ORDINATE(geometry,1)' ' SDO_GEOM.SDO_MAX_MBR_ORDINATE(geometry,2)')', 40986 ) RightEdge FROM SampleGeometry ) SELECT SDO_GEOM.SDO_INTERSECTION(SampleGeometry.geometry, MbrEdges.LeftEdge, 0.001) LeftMostPoint, SDO_GEOM.SDO_INTERSECTION(SampleGeometry.geometry, MbrEdges.RightEdge, 0.001) RightMostPoint FROM SampleGeometry, MbrEdges;  "Result" SDO_GEOMETRY(2001, 40986, NULL, SDO_ELEM_INFO_ARRAY(1, 1, 1), SDO_ORDINATE_ARRAY(6091825.78, 2271802.75)) "LeftMost" SDO_GEOMETRY(2001, 40986, NULL, SDO_ELEM_INFO_ARRAY(1, 1, 1), SDO_ORDINATE_ARRAY(6092445.07, 2271797.66))  "RightMost"
These examples only searched for polygon points that touched the left or right edges of the MBR. You could easily modify them to search for polygon points that touch the upper or lower edges of the MBR.WITH SampleGeometry AS ( SELECT SDO_GEOMETRY( 'POLYGON ((6091829.946 2271465.64, 6092444.797 2271460.591, 6092445.067 2271797.663, 6091825.777 2271802.748, 6091829.946 2271465.64))', 40986 ) geometry FROM dual ), LeftMbrEdge AS ( SELECT MIN(t.x) x FROM SampleGeometry, TABLE(SDO_UTIL.GETVERTICES(geometry)) t ), RightMbrEdge As ( SELECT MAX(t.x) x FROM SampleGeometry, TABLE(SDO_UTIL.GETVERTICES(geometry)) t ), LeftMostPoint As ( SELECT t.x, t.y FROM SampleGeometry, LeftMbrEdge, TABLE(SDO_UTIL.GETVERTICES(geometry)) t WHERE t.x = LeftMbrEdge.x ), RightMostPoint As ( SELECT t.x, t.y FROM SampleGeometry, RightMbrEdge, TABLE(SDO_UTIL.GETVERTICES(geometry)) t WHERE t.x = RightMbrEdge.x ) SELECT LeftMostPoint.*, RightMostPoint.* FROM LeftMostPoint, RightMostPoint;  "Result " 6091825.78 2271802.75 6092445.07 2271797.66
Regards,
Noel 
5. Re: Identifying Coordinate Positions in a Polygon
Stefan Jager May 14, 2013 2:46 AM (in response to user154136)Hi Robert,
No, such a function does not exist in the delivered functionality.
That said, it's easy enough to create a function that get's you the min and max X and Y from the SDO_ORDINATES. You could even do it with just SQL :)
Be aware though that if you do not compare properly you might end up with the MBR anyway, since that is essentially what and MBR is.
Out of curiosity, what do you need this for? And, if your user defines a diamond, how do you define top left and top right (or top left and bottom right)?
HTH,
Stefan
Noel must've posted when I was typing, did not see that last night, only noticed it this morning :). But there's your solution.
Edited by: Stefan Jager on May 14, 2013 9:45 AM 
6. Re: Identifying Coordinate Positions in a Polygon
user154136 May 13, 2013 2:07 PM (in response to Stefan Jager)Thanks Noel, I will look at your examples and apply them to my issue. Stefan, I need this for a custom tiling procedure I am working on where I have to divide a polygon into multiple polygons. i was using the sdo_sam tiling package but it was creating some oddly shaped tiles in some cases. Now, I am using the sdo_util tilt and bearing functions to divide the polygon up and i need to know what the top left and top right positions so that I can get the bearing and distance. I have a sdo_geometry object, so i can use this to determine the coordinate order since it will always be counter clockwise.
Thanks
Robert