argument in awk takes on the argument passing into bash script

User_U1UYA

Hi everybody,

To run my script: myscript copy -t "2011-11-11" -s 3

<-- the 2nd $OPTARG is "2011-11-11", so inside the script the awk calls for $2 and it took up the argument passed in instead of the 2nd column from free -g.

oth=$(free -g | grep 'Mem' | awk '{print $2}')

Please help.

Thanks

Herbert van den Bergh-Oracle

Can you attach your script here please. It doesn't look like you posted enough of it here to understand what is going on. It looks like there may be a quoting issue that is causing the $2 to get expanded by the shell, but we'd have to see the surrounding code to understand why.