Common annotation 1.1 on Javaee6

843830

import javax.annotation.Resource;
I try to use the following code for dependecy injection:

@Resource(lookup = "jms/javaee6/ConnectionFactory")
private static ConnectionFactory connectionFactory;
@Resource(lookup = "jms/javaee6/Queue")
private static Queue queue;

However, when I build with maven. The error message keeps showing
cannot find symbol
symbol : method lookup()
location: @interface javax.annotation.Resource

Anything i can do in order to make it works?

Thanks.

805009

That's because "lookup" isn't a valid method on javax.annotation.Resource. Try "name".

Nigel

843830

Thanks. Nigel

shelleyb

javax.annotation.Resource does include a "lookup" method as of Java EE 6.

http://download.oracle.com/javaee/6/api/javax/annotation/Resource.html#lookup()

shelleyb

The problem with building this in Maven is that the JDK also includes a javax.annotation.Resource which does not yet include the "lookup" method -

http://download.oracle.com/javase/6/docs/api/javax/annotation/Resource.html

In order to get it to build with Maven, you will need to add the JAR containing the correct javax.annotation.Resource to an endorsed JAR. This can be done by using the maven-dependency-plugin to copy the JAR to a directory, and then configuring the compiler plugin to reference the endorsed dir: -Djava.endorsed.dirs=${project.build.directory}/endorsed.

The following blog post includes more detailed information -
http://jaitechwriteups.blogspot.com/2011/02/resource-and-new-lookup-attribute-how.html

Nigel Deakin-Oracle

You're quite right, of course. @Resource(lookup="foo") is perfectly valid in Java EE 6, with several examples in the spec. Thanks for explaining why it doesn't always compile, even with Java EE 6 in the classpath.

Nigel