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How to access ShellFolder using a path

886787
Member Posts: 2 Blue Ribbon
Hi,
I would like to have the ShellFolder of a given path to browse its content.
Is there a solution to obtain an instance of the right File object pointing to the homeDirectory or ComputerDirectory or Network Directory giving <u> a path </u> (I don't know which one, this may include clsid) ?
thanks
I would like to have the ShellFolder of a given path to browse its content.
FileSystemView systemView = FileSystemView.getFileSystemView(); File homeDirectory = systemView.getHomeDirectory(); File[] files = systemView.getFiles(homeDirectory,false); File home2=new File(homeDirectory.getAbsolutePath()); File[] files1 = systemView.getFiles(home2, false); File[] files2 = home2.listFiles(); File[] files3 = homeDirectory.listFiles();When the home is obtained using FileSystemView, everything is fine (I obtain what I expect) in the list appear Computer, Network, ... but when I attempt to recreate the file using a path I obtain a subset of the previous result without Computer, Network, ... It just contains the list of "physical" files on the dirve, all "system" files are not present.
Is there a solution to obtain an instance of the right File object pointing to the homeDirectory or ComputerDirectory or Network Directory giving <u> a path </u> (I don't know which one, this may include clsid) ?
thanks
Answers
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Here is a not perfect solution:
private File createFolderByPath(String path) { File file = getLocalRepository(); String[] strings = path.split("/"); for (int i = 0; i < strings.length; i++) { String string = strings<em>;<br /> file = systemView.getChild(file, string);<br /> }<br /> return file;<br /> }<br /> <pre class="jive-pre"><code class="jive-code">If someone has a better idea...
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