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Need Day wise leave statistic report

I am trying to develop new day wise leave statistic report, as attachment , please check below code and suggest.
CREATE TABLE GET_DATES (DATE_START DATE,DATE_END DATE,PERSON_ID NUMBER);
INSERT INTO GET_DATES
VALUES (TO_DATE('11-MAY-2014'), TO_DATE('04-JUN-2014'),26876);
INSERT INTO GET_DATES
VALUES (TO_DATE('22-JAN-2017'), TO_DATE('22-MAR-2017'),26876);
COMMIT;
1. select date_start, date_end, date_end - date_start +1 days FROM GET_DATES;
the below query is working fine for one row, if more than 1 row its records are more than million.
but the desired output is to get correct days as attached file.
2. Select level - 1 lvl , date_start, date_end
FROM
(select date_start, date_end FROM GET_DATES
WHERE ROWNUM = 1)
connect by level <= (date_end - date_start)+ 1
3. Final query
select * from(
select date_start + lvl date_,
Trim(to_char(date_start + lvl, 'Day')) current_day_,
to_char(date_start + lvl, 'mm') month_,
to_char(date_start + lvl, 'YYYY') Year_
from (
Select level - 1 lvl , date_start, date_end
FROM
(select date_start, date_end FROM GET_DATES
WHERE ROWNUM = 1)
connect by
level <= (date_end - date_start)+ 1))
pivot (count(date_)date_ for current_day_ in
('Sunday' Sun,'Monday' Mon ,'Tuesday' Tue,'Wednesday' Wed,'Thursday' Thu,'Friday' Fri,'Saturday' Sat))
order by 2, 1;
“Thank you in advance”
Best Answers
-
Yes Sir, you suggested me to post in this forum, ..
1) This forum is for discussion of the use of the SQL Developer GUI tool. Your question is purely a SQL question. Better asked at https://community.oracle.com/tech/developers/categories/3063-general_questions1
Am testing code suggested by Mr. Soloman..
-
Next time provide version upfront, expecially when you are on very old version:
with t as ( select date_start + level - 1 dt from get_dates connect by rowid = prior rowid and level <= date_end - date_start + 1 and prior sys_guid() is not null ) select case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year, to_char(dt,'mm') month, sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday, sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday, sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday, sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday, sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday, sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday, sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday, count(*) grand_total from t group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm'))) order by to_char(dt,'yyyy'), to_char(dt,'mm') / YEAR MONTH SATURDAY SUNDAY MONDAY TUESDAY WEDNESDAY THURSDAY FRIDAY GRAND_TOTAL ---------- ----- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------- 05 3 3 3 3 3 3 3 21 06 1 1 1 1 4 2014 Total 3 4 4 4 4 3 3 25 01 1 2 2 2 1 1 1 10 02 4 4 4 4 4 4 4 28 03 3 3 3 3 4 3 3 22 2017 Total 8 9 9 9 9 8 8 60 7 rows selected. SQL>
SY.
Answers
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with t as ( select date_start + offset dt from get_dates, lateral( select level - 1 offset from dual connect by level <= date_end - date_start + 1 ) ) select case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year, to_char(dt,'mm') month, sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday, sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday, sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday, sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday, sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday, sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday, sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday, count(*) grand_total from t group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm'))) order by to_char(dt,'yyyy'), to_char(dt,'mm') / YEAR MO SATURDAY SUNDAY MONDAY TUESDAY WEDNESDAY THURSDAY FRIDAY GRAND_TOTAL ---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------- 05 3 3 3 3 3 3 3 21 06 1 1 1 1 4 2014 Total 3 4 4 4 4 3 3 25 01 1 2 2 2 1 1 1 10 02 4 4 4 4 4 4 4 28 03 3 3 3 3 4 3 3 22 2017 Total 8 9 9 9 9 8 8 60 7 rows selected. SQL>
SY.
-
You posted the exact same problem yesterday .... https://community.oracle.com/tech/developers/discussion/4483855/need-day-wise-leave-statistic-report#latest
-
Yes Sir, you suggested me to post in this forum, ..
1) This forum is for discussion of the use of the SQL Developer GUI tool. Your question is purely a SQL question. Better asked at https://community.oracle.com/tech/developers/categories/3063-general_questions1
Am testing code suggested by Mr. Soloman..
-
Yes Sir, you suggested me to post in this forum, ..
Ah, so I did. Mea culpa.
-
Thanks for the reply.
We are using 11g database.
Attached is the query execution output.
-
Next time provide version upfront, expecially when you are on very old version:
with t as ( select date_start + level - 1 dt from get_dates connect by rowid = prior rowid and level <= date_end - date_start + 1 and prior sys_guid() is not null ) select case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year, to_char(dt,'mm') month, sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday, sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday, sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday, sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday, sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday, sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday, sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday, count(*) grand_total from t group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm'))) order by to_char(dt,'yyyy'), to_char(dt,'mm') / YEAR MONTH SATURDAY SUNDAY MONDAY TUESDAY WEDNESDAY THURSDAY FRIDAY GRAND_TOTAL ---------- ----- ---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------- 05 3 3 3 3 3 3 3 21 06 1 1 1 1 4 2014 Total 3 4 4 4 4 3 3 25 01 1 2 2 2 1 1 1 10 02 4 4 4 4 4 4 4 28 03 3 3 3 3 4 3 3 22 2017 Total 8 9 9 9 9 8 8 60 7 rows selected. SQL>
SY.
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Many Thanks to you Mr. Solomon Yakobson Sir, Mr. EdSteven Sir, report working perfectly.