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Struts + ActionErrors + JDeveloper 10.1.3.4

655688Sep 8 2008 — edited Sep 9 2008
Hi, i'm working with Stuts and JDeveloper 10.1.3.4. My actions (DataPages) classes extends PageController. I wanna show struts error messages like using the saveErrors() method, but this method was removed since 10.1.3 version. How can i do that?. (sorry for my english, i'm Argentinian).

Thanks for your help.

Comments

AndrewSayer
Answer

You need to get the ip address of the parent for each row, you can use an analytic function here max(decode(is_parent,1,ip_address)) over (partition by parent_id)

And then it is trivial to order by is_parent desc:

with ctrl as (

select 100 rec_id,       'Record 1    ' description ,    1000 parent_id, '80.160.4.5  ' ip_address,  1 is_parent from dual union all

select 101 rec_id,       'child       ' description ,    1000 parent_id, '169.60.5.20 ' ip_address,  0 is_parent from dual union all

select 105 rec_id,       'child       ' description ,    1000 parent_id, '169.60.5.20 ' ip_address,  0 is_parent from dual union all

select 103 rec_id,       'Record 2    ' description ,    1002 parent_id, '80.160.4.3  ' ip_address,  1 is_parent from dual union all

select 104 rec_id,       'child       ' description ,    1002 parent_id, '169.60.2.5  ' ip_address,  0 is_parent from dual union all

select 102 rec_id,       'Record 3    ' description ,    1001 parent_id, '80.160.4.2  ' ip_address,  1 is_parent from dual)

select *

From ctrl order by max(decode(is_parent,1,ip_address)) over (partition by parent_id), is_parent desc

/

    REC_ID DESCRIPTION   PARENT_ID IP_ADDRESS    IS_PARENT

---------- ------------ ---------- ------------ ----------

       102 Record 3           1001 80.160.4.2            1

       103 Record 2           1002 80.160.4.3            1

       104 child              1002 169.60.2.5            0

       100 Record 1           1000 80.160.4.5            1

       101 child              1000 169.60.5.20           0

       105 child              1000 169.60.5.20           0

Marked as Answer by 3288275 · Sep 27 2020
unknown-7404

If you have hierarchical data use a hierarchical query. The result tree will have the parents and children together.

See the examples queries in the Oracle documentation

https://docs.oracle.com/database/121/SQLRF/queries003.htm#SQLRF52335

Hierarchical Query Examples

CONNECT BY Example The following hierarchical query uses

the CONNECT BY clause to define the relationship between employees and managers:

SELECT employee_id, last_name, manager_id

   FROM employees

   CONNECT BY PRIOR employee_id = manager_id;

EMPLOYEE_ID LAST_NAME                 MANAGER_ID

----------- ------------------------- ----------

        101 Kochhar                          100

        108 Greenberg                        101

        109 Faviet                           108

        110 Chen                             108

        111 Sciarra                          108

        112 Urman                            108

        113 Popp                             108

        200 Whalen                           101

        203 Mavris                           101

        204 Baer                             101

. . .

Barbara Boehmer

SCOTT@orcl_12.1.0.2.0> select rec_id, description, parent_id, ip_address, is_parent

  2  from  database_table

  3  start  with is_parent=1

  4  connect by prior parent_id = parent_id

  5          and prior is_parent = is_parent + 1

  6  order  siblings by ip_address

  7  /

    REC_ID DESCRIPTION  PARENT_ID IP_ADDRESS  IS_PARENT

---------- ----------- ---------- ----------- ----------

      102 Record 3          1001 80.160.4.2          1

      103 Record 2          1002 80.160.4.3          1

      104 child            1002 169.60.2.5          0

      100 Record 1          1000 80.160.4.5          1

      101 child            1000 169.60.5.20          0

      105 child            1000 169.60.5.20          0

6 rows selected.

3288275

Thank you Andrew Sayer ....  That was an awesome solution!

Pablolee

@3288275

Whilst your sample data does  not show it, is it possible that in a scenario where you have >1 child record of a specific parent that the IP addresses are different (rather than your current data scenario where both IP addresses for this situation are the same: 169.60.5.20  )     

If so, then you'll need to add another sort to the list (or take a closer look at Barbara's solution)

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