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REGEXP_SUBSTR question

John O'TooleFeb 25 2009 — edited Sep 14 2010
Folks, I'm trying to use REGEXP_SUBSTR to find the piece of text between the second last and last occurrence of a backslash. I can find the text between any specified occurrences of backslashes when I start at the front, but I don't know how many backslashes there will be in the string.
I'm on 10g R2, so don't have access to REGEXP_COUNT.
WITH test_data AS (
SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL
)
SELECT t, REGEXP_SUBSTR(t,'[^\]+', 1, 3) my_string
FROM test_data;
The REGEXP_SUBSTR in that example gives me the third occurrence, which isn't quite right. The output I would like is:
folderA
temp
A
B
C
D
folderE
Many Thanks.
This post has been answered by Karthick2003 on Feb 25 2009
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Comments

Gurjas
You should create a bitmap or btree index on the action_id of the history table depending on the cardinality of the column.
Which will fasten the checking of action usage in the history table.

As per my understanding the isused idea is not good.

Why don't you go for the foreign key in the table? If you have already implement the foreign key in the table then this problem should not be there.. now you have to check the existense manually in the table. If possible you can also implement the foreign key now.
668031
Thanks,
after all they did create a index. The problem of having a foreign key without having a index by that key is that it takes very long to check if it is used.
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Locked on Oct 12 2010
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