REGEXP_SUBSTR question

John O'Toole

Folks, I'm trying to use REGEXP_SUBSTR to find the piece of text between the second last and last occurrence of a backslash. I can find the text between any specified occurrences of backslashes when I start at the front, but I don't know how many backslashes there will be in the string.
I'm on 10g R2, so don't have access to REGEXP_COUNT.

WITH test_data AS (
SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL
)
SELECT t, REGEXP_SUBSTR(t,'[^\]+', 1, 3) my_string
FROM test_data;

The REGEXP_SUBSTR in that example gives me the third occurrence, which isn't quite right. The output I would like is:

folderA
temp
A
B
C
D
folderE

Many Thanks.

Karthick2003

Without regexp

SQL> WITH test_data AS (
  2  SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
  3  SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
  4  SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
  5  SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
  6  SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
  7  SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
  8  SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL
  9  )
 10  SELECT t, substr(t, instr(t,'\',-1,2)+1, (instr(t,'\',-1,1)-instr(t,'\',-1,2))-1) my_string
 11  FROM test_data;

T                                      MY_STRING
-------------------------------------- --------------------------------------
c:\temp\folderA\fileA.txt              folderA
c:\temp\fileA.txt                      temp
\\mymachine\A\fileB.txt                A
\\mymachine\A\B\fileB.txt              B
\\mymachine\A\B\C\image.jpg            C
\\mymachine\A\B\C\D\music.mpg          D
c:\myfolder\folderD\folderE\4969-A.txt folderE

Karthick2003

Without regexp

SQL> WITH test_data AS (
  2  SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
  3  SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
  4  SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
  5  SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
  6  SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
  7  SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
  8  SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL
  9  )
 10  SELECT t, substr(t, instr(t,'\',-1,2)+1, (instr(t,'\',-1,1)-instr(t,'\',-1,2))-1) my_string
 11  FROM test_data;

T                                      MY_STRING
-------------------------------------- --------------------------------------
c:\temp\folderA\fileA.txt              folderA
c:\temp\fileA.txt                      temp
\\mymachine\A\fileB.txt                A
\\mymachine\A\B\fileB.txt              B
\\mymachine\A\B\C\image.jpg            C
\\mymachine\A\B\C\D\music.mpg          D
c:\myfolder\folderD\folderE\4969-A.txt folderE

BluShadow

Easier to use REGEXP_REPLACE to remove everything you don't want...

SQL> ed
Wrote file afiedt.buf

  1  WITH test_data AS (
  2  SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
  3  SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
  4  SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
  5  SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
  6  SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
  7  SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
  8  SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL
  9  )
 10  select regexp_replace(t, '^.*[\]([^\]*)[\][^\]*$','\1')
 11* from test_data
SQL> /

REGEXP_REPLACE(T,'^.*[\]([^\]*)[\][^\]*$','\1')
------------------------------------------------------------------
folderA
temp
A
B
C
D
folderE

7 rows selected.

SQL>

John O'Toole

Perfect. With all this REGEXP lark around, its sometimes easy to forget about the old skool string functions.
Thanks

Aketi Jyuuzou

col str for a20

WITH test_data AS (
SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL)
select t,RegExp_replace(t,'^.*?([^\]+)\\[^\]+$','\1') as str
  from test_data
order by t;

T                                       STR
--------------------------------------  -------
\\mymachine\A\B\C\D\music.mpg           D
\\mymachine\A\B\C\image.jpg             C
\\mymachine\A\B\fileB.txt               B
\\mymachine\A\fileB.txt                 A
c:\myfolder\folderD\folderE\4969-A.txt  folderE
c:\temp\fileA.txt                       temp
c:\temp\folderA\fileA.txt               folderA

And I used regexp_count B-)

select t,RegExp_substr(t,'[^\]+',1,-1+regexp_count(t,'[^\]+')) as str
  from test_data
order by t;

LostWorld

How do you people learn all this? where from you get these requirements and how do you find out which all functions you can apply at what scenario? Most of these oracle fucntions we don't use normally.


Amzing i must say

Kanish

It is really amazing, Could you explain me step by step.

kanish