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finding the min date of different dataset and pivoting

DevxMar 7 2020 — edited Mar 7 2020

Hi everyone,

i have a scenario where i want to find the min dates from multiple tables that contain different date field. let me explain further. please consider the following data

with summ as

(

SELECT 8521 AS cid, 'partial' as status, to_date('2/16/2015 8:54:00 AM', 'mm/dd/yyyy hh:mi:ss am') as ev_dt, 123 as v_id from dual union all

SELECT 1428 AS cid, 'partial' as status,to_date('2/15/2015 5:28:00 PM', 'mm/dd/yyyy hh:mi:ss am') as ev_dt, 123 as v_id from dual union all

SELECT 7364 AS cid, 'complete' as status ,to_date('2/16/2015 2:15:00 AM', 'mm/dd/yyyy hh:mi:ss am') as ev_dt, 123 as v_id from dual union all

SELECT 8965 AS cid, 'complete' as status ,to_date('2/15/2015 8:03:00 PM', 'mm/dd/yyyy hh:mi:ss am') as ev_dt, 123 as v_id from dual union all

SELECT 6361 AS cid, 'complete' as status ,to_date('2/15/2015 8:17:00 PM', 'mm/dd/yyyy hh:mi:ss am') as ev_dt, 123 as v_id from dual union all

SELECT 6935 AS cid, 'partial' as status , to_date('2/16/2015 1:57:00 AM', 'mm/dd/yyyy hh:mi:ss am') as ev_dt, 123 as v_id from dual

)

,orders as

(

SELECT 8521 AS cid, 'attending' as data_val, to_date('2/16/2015 8:17:00 AM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 8521 AS cid, 'phone' as data_val, to_date('2/16/2015 8:17:00 AM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 8521 AS cid, 'md' as data_val, to_date('2/16/2015 8:17:00 AM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 1428 AS cid, 'attending' as data_val, to_date('2/15/2015 4:59:00 PM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 1428 AS cid, 'phone' as data_val, to_date('2/15/2015 4:59:00 PM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 1428 AS cid, 'md' as data_val, to_date('2/15/2015 4:59:00 PM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 8965 AS cid, 'attending' as data_val, to_date('2/15/2015 8:01:00 PM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 8965 AS cid, 'phone' as data_val, to_date('2/15/2015 8:01:00 PM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 8965 AS cid, 'md' as data_val, to_date('2/15/2015 8:01:00 PM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 6935 AS cid, 'attending' as data_val, to_date('2/16/2015 1:57:00 AM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 6935 AS cid, 'phone' as data_val, to_date('2/16/2015 1:57:00 AM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual union all

SELECT 6935 AS cid, 'md' as data_val, to_date('2/16/2015 1:57:00 AM', 'mm/dd/yyyy hh:mi:ss am') as or_dt, 123 as v_id from dual

)

,detail as

(

SELECT 8521 AS cid, 'date_Read' as data_val, to_date('3/17/2015 8:17:00 AM', 'mm/dd/yyyy hh:mi:ss am') as date_Read, 123 as v_id from dual union all

SELECT 1428 AS cid, 'date_Read' as data_val, to_date('2/24/2015 4:59:00 PM', 'mm/dd/yyyy hh:mi:ss am') as date_Read, 123 as v_id from dual union all

SELECT 8965 AS cid, 'date_Read' as data_val, to_date('3/31/2015 8:01:00 PM', 'mm/dd/yyyy hh:mi:ss am') as date_Read, 123 as v_id from dual union all

SELECT 6935 AS cid, 'date_Read' as data_val, to_date('2/25/2015 1:57:00 AM', 'mm/dd/yyyy hh:mi:ss am') as date_Read, 123 as v_id from dual

)

i want to join all 3 tables (summ, orders,detail) by cid, v_id and i want to find the following.

from summ table i want to find the row with min ev_dt where status is complete. from orders table i want to find the row with min or_dt

and from detail table i want to find out the row with min date_Read. my output should look like this

vi_id first_complete first_ordered first_read

123 2/15/2015 8:03:00 PM 2/15/2015 4:59:00 PM 2/24/2015 4:59:00 PM

my query looks like this but it is not completed

select * from (

SELECT row_number () over (partition by v_id , status order by ev_dt) as first_completed,

row_number () over (partition by v_id order by ord_dt) as first_ordered,

row_number () over (partition by v_id order by date_Read) as first_read

FROM summ a

JOIN orders b

on (a.v_id = b._vid)

JOIN detail c

on (a.v_id = c.v_id)

) where first_completed = 1 or (first_ordered = 1 and status='complete')

or first_read = 1

can someone help me modify my query so that i can get the output describe above? im using oracle 11g

thanks in advance

722698

create or replace function add_working_days(
p_days in number,
p_dt in date default trunc(sysdate)
)
return date
as
v_weeks number;
v_adj number;
begin

v_weeks := trunc(p_days/5);

if to_number(to_char(p_dt,'D')) + mod(p_days,5) >= 7 then
v_adj := 2;
else
v_adj := 0;
end if;

return p_dt + 7*v_weeks + v_adj+mod(p_days,5);
end add_working_days;

This is not working correct if the date is SATURDAY, but seems working M-F and Sunday

select trunc(sysdate)+4,add_working_days(6,trunc(sysdate)+4) from dual;
Output : 19-sep2009 29-Sep-2009

722698

Frank Kulash

Hi, Niren,

[This thread|http://forums.oracle.com/forums/thread.jspa?messageID=3351822&#3351822] should give you some ideas. It does it without using PL/SQL, so it's actually a harder problem.

In PL/SQL, you could loop through the days, starting with the start_date parameter and decrementing a counter that is initialized to the other parameter, stopping when the counter reaches 0.
Or you could write a recursive function.

Arunkumar Ramamoorthy-Oracle

Like this?

SQL> ed
Wrote file afiedt.buf

create or replace function next_working_day(start_date in date,  add_days in number) return date is
return_date date;
begin
return_date:=start_date+add_days;
if (UPPER(to_char(return_date,'FMDAY'))='SATURDAY') then
return_date:=return_date+2;
elsif (UPPER(to_char(return_date,'FMDAY'))='SUNDAY') then
return_date:=return_date+1;
end if;
return return_date;
end;
SQL> /

Function created.

SQL> select next_working_day('10-AUG-2009',10) FROM DUAL;

NEXT_WORK
---------
20-AUG-09

SQL> select next_working_day('11-SEP-2009',1) from dual;

NEXT_WORK
---------
14-SEP-09

SQL>

-Arun

Tested

Posted after testing

722698

Hi Frant,

Please explain me with an example. If you have the exact function/Procedure than it can really help.

Thanks
Niren

Frank Kulash

Hi, Niren,

The first respondent gave a better function for testing for work days (Monday through Friday). If there's a bug with Saturdays, I'm sure that can fixed. Also,that function depends on your NLS settings. If that's an issue for you, that can be fixed, too. The idea that there are 5 work days in any 7 consecutive days will cut down the execution time considerable.

A function like I suggested would be useful if you had to consider holidays as well as weekends.
Here's an untested example:

CREATE OR REPLACE FUNCTION  work_days_away
(      in_start_date	    DATE
,      in_day_cnt	    NUMBER
)
RETURN	DATE
DETERMINISTIC
IS
(
	IF  in_start_date - TRUNC (in_start_date, 'IW') >= 5
	OR  is_holiday (in_start_date)
	THEN
		RETURN  work_days_away ( in_start_date + 1
				       , in_day_cnt
				       );
	ELSIF  in_day_cnt >= 1
	THEN
		RETURN  work_days_away ( in_start_date + 1
				       , in_day_cnt    - 1
				       );
	ELSE
		RETURN  in_start_date;
	END IF;
END	work_days_away;

This use the date format 'IW', which does not depend on NLS settings, rather than 'D', which does.

722698

Hi Arun,

The code example where 10-AUG-2009 + 10 days should return 22 as per the need but your code is not considering the saturday and sunday falling on 15,16 Aug 2009.

Thanks
Niren

Arunkumar Ramamoorthy-Oracle

Hi,

I was under the impression that, after adding the days, if the result falls on saturday / sunday, it should consider that and return the next working day i.e monday.

So, 10-AUG-2009 + 10 = 20-AUG-2009 which falls on Thursday.
11-SEP-2009 + 1 = 12-SEP-2009 which falls on Saturday. So, the next working day is Monday which is 14-Sep-2009.

Please let me know if my understanding about your requirement is not correct.

-Arun

722698

Hi Arun,

Basically the need is that any number of days added to a date should return date excluding all saturdays and sundays falling in between.
It would be great if you could help me on this .

Thanks
Niren
+919873314561

Arunkumar Ramamoorthy-Oracle

How about this?

create or replace function add_working_days(
p_days in number,
p_dt in date default trunc(sysdate)
)
return date
as
v_weeks number;
v_adj number;
begin

v_weeks := trunc(p_days/5);

if to_number(to_char(p_dt,'D')) + mod(p_days,5) <= 6 then
v_adj := 1;
elsif to_number(to_char(p_dt,'D')) + mod(p_days,5) = 7 then
v_adj := 2;
else
v_adj := 0;
end if;

return p_dt + 7*v_weeks + v_adj+mod(p_days,5);
end add_working_days;

-Arun

Untested

Shahid Ali

Dear User,
Simple Select can be used to get the desired result.

Solution is :
select decode(to_char((<your_date> + <days_to_add>),'FMDAY'),'SATURDAY',(((<your_date> + <days_to_add>) +2 ,'SUNDAY' ,(((<your_date> + <days_to_add> ) +1, (((<your_date> + <days_to_add> )) from dual;

Examples :
For sysdate as 16 sep 09

Case 1 : Sunday
SQL> select decode(to_char((sysdate + 4),'FMDAY'),'SATURDAY',(sysdate + 4 ) +2 ,'SUNDAY' ,(sysdate + 4 ) +1, (sysdate + 4 )) from dual;

DECODE(TO
---------
21-SEP-09

Case 2 : Saturday
SQL> select decode(to_char((sysdate + 3),'FMDAY'),'SATURDAY',(sysdate + 3 ) +2 ,'SUNDAY' ,(sysdate + 3 ) +1, (sysdate + 3 )) from dual;

DECODE(TO
---------
21-SEP-09

Case 2 : Week day
SQL> select decode(to_char((sysdate + 2 ),'FMDAY'),'SATURDAY',(sysdate + 2 ) +2 ,'SUNDAY' ,(sysdate + 2 ) +1, (sysdate + 2 )) from dual;

DECODE(TO
---------
18-SEP-09

Revert me back in case of any confusion .

Sven W.

user3021403 wrote:
Hi Friends,

I need a funtion which can take in parameters as start_date and number , sum them as new date and return new_start_date as workind day.
Suppose '15-SEP-2009' + 6 should return 23-SEP-2009 as new date.
Basically the sum of date and number should return next working day (excluding saturday,sunday).
e.g '15-SEP-2009' + 6 =21-SEP-2009 , but it includes saturday and sunday , so it should return 23-SEP-2009.

Thanks
Niren

I've written such a logic some years ago. I think you have already given some usable results. Just a few comments from my own experience. There are special scenarios you should think about, how you want to handle them.

1) You add a weekend as date and add 0. Should the next monday be returned or should it stay at the weekend day?
2) Is the number parameter the number of workdays added or the number of days? Like: What should the result be if you add 20 days, will all weekends be skipped? You already gave a clear definition, but it should be specifically mentioned that the number to add is not a number of working days.
3) At a later point you might want to include holidays too (from a holiday table, for example)
4) What about negative numbers? Can your function also calculate back in time? Do you want the friday in this case or the next monday?

722698

Hi Friends,

Thanks for the reply, i have developed the solution.
Sending the code for the benefit of others.

CREATE OR REPLACE FUNCTION NIREN_ADD_DAYS (
p_date DATE,
p_days NUMBER
)
RETURN DATE
IS

v_date DATE;
v_count NUMBER;

BEGIN

SELECT
DECODE(
RTRIM(TO_CHAR(p_date, 'DAY')),
'SATURDAY',
NEXT_DAY(p_date, 'SUNDAY'),
NEXT_DAY((p_date - 7), 'SUNDAY')
)
INTO
v_date
FROM
dual;

v_count := p_date - v_date;

IF (v_count = -1)
THEN

v_count := 0;

END IF;

v_count := v_count + p_days;

IF (v_count > 5)
THEN

v_count := v_count + (FLOOR(v_count / 5.1) * 2);

END IF;

RETURN (v_date + v_count);

END NIREN_ADD_DAYS;
/

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Added on Mar 7 2020

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finding the min date of different dataset and pivoting

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