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Can DB 18c XE, APEX 21.1 and ORDS 21.1 be installed on Windows 7 Professional?

Bill CarlisleOct 26 2021

Hi,
Can DB 18c XE, APEX 21.1 and ORDS 21.1 be installed on Windows 7 Professional?
Windows 7 Professional Service Pack 1 on a Dell Optiplex 990 CORE i5 vPro, 16 Gig RAM,

Searched and searched found nothing...

I've installed DB 18c XE successfully on Windows 7
installed APEX 21.1 in the XEPDB1 pluggable DB (1st time with multi-tenant) until the apex_rest_config.sql - got error "GetConsoleMode failed. LastError=[6]" in ReadKey.pm
called from concatExec in concat.pl
My 1st time installing in a multi-tenant database.

Should I switch to different versions ? Just trying to install for learning local install with the newest versions..

Thank you, Bill

Comments

Solomon Yakobson
with t as (
           select  date_start + offset dt
             from  get_dates,
                   lateral(
                           select  level - 1 offset
                             from  dual
                             connect by level <= date_end - date_start + 1
                          )
          )
select  case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year,
        to_char(dt,'mm') month,
        sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday,
        sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday,
        sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday,
        sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday,
        sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday,
        sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday,
        sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday,
        count(*) grand_total
  from  t
  group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm')))
  order by to_char(dt,'yyyy'),
           to_char(dt,'mm')
/

YEAR       MO   SATURDAY     SUNDAY     MONDAY    TUESDAY  WEDNESDAY   THURSDAY     FRIDAY GRAND_TOTAL
---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ---------- -----------
           05          3          3          3          3          3          3          3          21
           06                     1          1          1          1                                 4
2014 Total             3          4          4          4          4          3          3          25
           01          1          2          2          2          1          1          1          10
           02          4          4          4          4          4          4          4          28
           03          3          3          3          3          4          3          3          22
2017 Total             8          9          9          9          9          8          8          60


7 rows selected.


SQL>

SY.

Shaik_Muhammad
Answer

Yes Sir, you suggested me to post in this forum, ..

  1. This forum is for discussion of the use of the SQL Developer GUI tool. Your question is purely a SQL question. Better asked at https://community.oracle.com/tech/developers/categories/3063-general_questions1
    Am testing code suggested by Mr. Soloman..
Marked as Answer by Shaik_Muhammad · Jun 8 2021
EdStevens

Yes Sir, you suggested me to post in this forum, ..
Ah, so I did. Mea culpa.

Shaik_Muhammad

Thanks for the reply.
We are using 11g database.
Attached is the query execution output.
query_execution.jpg (67.13 KB)

Solomon Yakobson

Next time provide version upfront, expecially when you are on very old version:

with t as (
           select  date_start + level - 1 dt
             from  get_dates
             connect by rowid = prior rowid
                    and level <= date_end - date_start + 1
                    and prior sys_guid() is not null
          )
select  case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year,
        to_char(dt,'mm') month,
        sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday,
        sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday,
        sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday,
        sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday,
        sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday,
        sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday,
        sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday,
        count(*) grand_total
  from  t
  group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm')))
  order by to_char(dt,'yyyy'),
           to_char(dt,'mm')
/


YEAR       MONTH   SATURDAY     SUNDAY     MONDAY    TUESDAY  WEDNESDAY   THURSDAY     FRIDAY GRAND_TOTAL
---------- ----- ---------- ---------- ---------- ---------- ---------- ---------- ---------- -----------
           05             3          3          3          3          3          3          3          21
           06                        1          1          1          1                                 4
2014 Total                3          4          4          4          4          3          3          25
           01             1          2          2          2          1          1          1          10
           02             4          4          4          4          4          4          4          28
           03             3          3          3          3          4          3          3          22
2017 Total                8          9          9          9          9          8          8          60


7 rows selected.


SQL>

SY.

Shaik_Muhammad

Many Thanks to you Mr. Solomon Yakobson Sir, Mr. EdSteven Sir, report working perfectly.

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Added on Oct 26 2021
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