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Is it possible to use oracle wallets with autologin for the connection authentication?

YevonMay 4 2022

At first I didn't understand why it was asking me to specify a wallet if the password is mandatory anyway. Is the wallet only used for ssl certificates? Is there any way to setup the extension to authenticate through stored wallet credentials? I'm able to do so in the command line just specifying sqlplus /@TNS_CONNECTION_NAME
This post has been answered by Christian.Shay -Oracle on May 10 2022
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Solomon Yakobson 
with t as (
           select  date_start + offset dt
             from  get_dates,
                   lateral(
                           select  level - 1 offset
                             from  dual
                             connect by level <= date_end - date_start + 1
                          )
          )
select  case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year,
        to_char(dt,'mm') month,
        sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday,
        sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday,
        sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday,
        sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday,
        sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday,
        sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday,
        sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday,
        count(*) grand_total
  from  t
  group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm')))
  order by to_char(dt,'yyyy'),
           to_char(dt,'mm')
/

YEAR       MO   SATURDAY     SUNDAY     MONDAY    TUESDAY  WEDNESDAY   THURSDAY     FRIDAY GRAND_TOTAL
---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ---------- -----------
           05          3          3          3          3          3          3          3          21
           06                     1          1          1          1                                 4
2014 Total             3          4          4          4          4          3          3          25
           01          1          2          2          2          1          1          1          10
           02          4          4          4          4          4          4          4          28
           03          3          3          3          3          4          3          3          22
2017 Total             8          9          9          9          9          8          8          60


7 rows selected.


SQL>

SY.

EdStevens

You posted the exact same problem yesterday .... https://community.oracle.com/tech/developers/discussion/4483855/need-day-wise-leave-statistic-report#latest

Shaik_Muhammad
Answer

Yes Sir, you suggested me to post in this forum, ..

  1. This forum is for discussion of the use of the SQL Developer GUI tool. Your question is purely a SQL question. Better asked at https://community.oracle.com/tech/developers/categories/3063-general_questions1
    Am testing code suggested by Mr. Soloman..
Marked as Answer by Shaik_Muhammad · Jun 8 2021
EdStevens

Yes Sir, you suggested me to post in this forum, ..
Ah, so I did. Mea culpa.

Shaik_Muhammad

Thanks for the reply.
We are using 11g database.
Attached is the query execution output.
query_execution.jpg (67.13 KB)

Solomon Yakobson

Next time provide version upfront, expecially when you are on very old version:

with t as (
           select  date_start + level - 1 dt
             from  get_dates
             connect by rowid = prior rowid
                    and level <= date_end - date_start + 1
                    and prior sys_guid() is not null
          )
select  case grouping(to_char(dt,'mm')) when 1 then to_char(dt,'yyyy') || ' Total' end year,
        to_char(dt,'mm') month,
        sum(case dt - trunc(dt,'iw') when 5 then 1 end) saturday,
        sum(case dt - trunc(dt,'iw') when 6 then 1 end) sunday,
        sum(case dt - trunc(dt,'iw') when 0 then 1 end) monday,
        sum(case dt - trunc(dt,'iw') when 1 then 1 end) tuesday,
        sum(case dt - trunc(dt,'iw') when 2 then 1 end) wednesday,
        sum(case dt - trunc(dt,'iw') when 3 then 1 end) thursday,
        sum(case dt - trunc(dt,'iw') when 4 then 1 end) friday,
        count(*) grand_total
  from  t
  group by grouping sets((to_char(dt,'yyyy')),(to_char(dt,'yyyy'),to_char(dt,'mm')))
  order by to_char(dt,'yyyy'),
           to_char(dt,'mm')
/


YEAR       MONTH   SATURDAY     SUNDAY     MONDAY    TUESDAY  WEDNESDAY   THURSDAY     FRIDAY GRAND_TOTAL
---------- ----- ---------- ---------- ---------- ---------- ---------- ---------- ---------- -----------
           05             3          3          3          3          3          3          3          21
           06                        1          1          1          1                                 4
2014 Total                3          4          4          4          4          3          3          25
           01             1          2          2          2          1          1          1          10
           02             4          4          4          4          4          4          4          28
           03             3          3          3          3          4          3          3          22
2017 Total                8          9          9          9          9          8          8          60


7 rows selected.


SQL>

SY.

1 person found this helpful
Shaik_Muhammad

Many Thanks to you Mr. Solomon Yakobson Sir, Mr. EdSteven Sir, report working perfectly.

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Added on May 4 2022
#oracle-developer-tools-for-vs-code
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