Function in param, start_date & number , return sums next working day

722698 · Sep 15, 2009 2:03PM

Hi Friends,

I need a funtion which can take in parameters as start_date and number , sum them as new date and return new_start_date as workind day.
Suppose '15-SEP-2009' + 6 should return 23-SEP-2009 as new date.
Basically the sum of date and number should return next working day (excluding saturday,sunday).
e.g '15-SEP-2009' + 6 =21-SEP-2009 , but it includes saturday and sunday , so it should return 23-SEP-2009.

Thanks
Niren

722698 · Sep 15, 2009 2:08PM

create or replace function add_working_days(
p_days in number,
p_dt in date default trunc(sysdate)
)
return date
as
v_weeks number;
v_adj number;
begin

v_weeks := trunc(p_days/5);

if to_number(to_char(p_dt,'D')) + mod(p_days,5) >= 7 then
v_adj := 2;
else
v_adj := 0;
end if;

return p_dt + 7*v_weeks + v_adj+mod(p_days,5);
end add_working_days;

This is not working correct if the date is SATURDAY, but seems working M-F and Sunday

select trunc(sysdate)+4,add_working_days(6,trunc(sysdate)+4) from dual;
Output : 19-sep2009 29-Sep-2009

722698 · Sep 15, 2009 2:09PM

create or replace function add_working_days(
p_days in number,
p_dt in date default trunc(sysdate)
)
return date
as
v_weeks number;
v_adj number;
begin

v_weeks := trunc(p_days/5);

if to_number(to_char(p_dt,'D')) + mod(p_days,5) >= 7 then
v_adj := 2;
else
v_adj := 0;
end if;

return p_dt + 7*v_weeks + v_adj+mod(p_days,5);
end add_working_days;

This is not working correct if the date is SATURDAY, but seems working M-F and Sunday

select trunc(sysdate)+4,add_working_days(6,trunc(sysdate)+4) from dual;
Output : 19-sep2009 29-Sep-2009

Frank Kulash · Sep 15, 2009 2:09PM

Hi, Niren,

[This thread|http://forums.oracle.com/forums/thread.jspa?messageID=3351822&#3351822] should give you some ideas. It does it without using PL/SQL, so it's actually a harder problem.

In PL/SQL, you could loop through the days, starting with the start_date parameter and decrementing a counter that is initialized to the other parameter, stopping when the counter reaches 0.
Or you could write a recursive function.

Arunkumar Ramamoorthy-Oracle · Sep 15, 2009 2:12PM

Like this?

SQL> ed
Wrote file afiedt.buf

create or replace function next_working_day(start_date in date,  add_days in number) return date is
return_date date;
begin
return_date:=start_date+add_days;
if (UPPER(to_char(return_date,'FMDAY'))='SATURDAY') then
return_date:=return_date+2;
elsif (UPPER(to_char(return_date,'FMDAY'))='SUNDAY') then
return_date:=return_date+1;
end if;
return return_date;
end;
SQL> /

Function created.

SQL> select next_working_day('10-AUG-2009',10) FROM DUAL;

NEXT_WORK
---------
20-AUG-09

SQL> select next_working_day('11-SEP-2009',1) from dual;

NEXT_WORK
---------
14-SEP-09

SQL>

-Arun

Tested

Posted after testing

722698 · Sep 15, 2009 2:15PM

Hi Frant,

Please explain me with an example. If you have the exact function/Procedure than it can really help.

Thanks
Niren

Frank Kulash · Sep 15, 2009 3:31PM

Hi, Niren,

The first respondent gave a better function for testing for work days (Monday through Friday). If there's a bug with Saturdays, I'm sure that can fixed. Also,that function depends on your NLS settings. If that's an issue for you, that can be fixed, too. The idea that there are 5 work days in any 7 consecutive days will cut down the execution time considerable.

A function like I suggested would be useful if you had to consider holidays as well as weekends.
Here's an untested example:

CREATE OR REPLACE FUNCTION  work_days_away
(      in_start_date	    DATE
,      in_day_cnt	    NUMBER
)
RETURN	DATE
DETERMINISTIC
IS
(
	IF  in_start_date - TRUNC (in_start_date, 'IW') >= 5
	OR  is_holiday (in_start_date)
	THEN
		RETURN  work_days_away ( in_start_date + 1
				       , in_day_cnt
				       );
	ELSIF  in_day_cnt >= 1
	THEN
		RETURN  work_days_away ( in_start_date + 1
				       , in_day_cnt    - 1
				       );
	ELSE
		RETURN  in_start_date;
	END IF;
END	work_days_away;

This use the date format 'IW', which does not depend on NLS settings, rather than 'D', which does.

722698 · Sep 15, 2009 11:22PM

Hi Arun,

The code example where 10-AUG-2009 + 10 days should return 22 as per the need but your code is not considering the saturday and sunday falling on 15,16 Aug 2009.

Thanks
Niren

Arunkumar Ramamoorthy-Oracle · Sep 16, 2009 2:02AM

Hi,

I was under the impression that, after adding the days, if the result falls on saturday / sunday, it should consider that and return the next working day i.e monday.

So, 10-AUG-2009 + 10 = 20-AUG-2009 which falls on Thursday.
11-SEP-2009 + 1 = 12-SEP-2009 which falls on Saturday. So, the next working day is Monday which is 14-Sep-2009.

Please let me know if my understanding about your requirement is not correct.

-Arun

722698 · Sep 16, 2009 2:51AM

Hi Arun,

Basically the need is that any number of days added to a date should return date excluding all saturdays and sundays falling in between.
It would be great if you could help me on this .

Thanks
Niren
+919873314561

Arunkumar Ramamoorthy-Oracle · Sep 16, 2009 3:46AM

How about this?

create or replace function add_working_days(
p_days in number,
p_dt in date default trunc(sysdate)
)
return date
as
v_weeks number;
v_adj number;
begin

v_weeks := trunc(p_days/5);

if to_number(to_char(p_dt,'D')) + mod(p_days,5) <= 6 then
v_adj := 1;
elsif to_number(to_char(p_dt,'D')) + mod(p_days,5) = 7 then
v_adj := 2;
else
v_adj := 0;
end if;

return p_dt + 7*v_weeks + v_adj+mod(p_days,5);
end add_working_days;

-Arun

Untested

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