Java SE (Java Platform, Standard Edition)

OK, I figured out that I needed to parse the DataInputStream.... so:

try {
            u = new URL("http://www.google.com"); 
            is = u.openStream(); 
            dis = new DataInputStream(new BufferedInputStream(is)); 
            DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
            docBuilderFactory.setIgnoringComments(true);
            docBuilderFactory.setValidating(false);
            DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
            Document doc = docBuilder.parse(dis);  // The exception is caught here.....

        } catch (Exception ex) {
               System.out.println(ex.getMessage());
         }

But now I get this exception:
class org.xml.sax.SAXParseException
The entity name must immediately follow the '&' in the entity reference.

Any idea?

Or in other words...

What is the best way to parse a URL and ignore all SAXParseException.

DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document doc = docBuilder.parse("http://www.gogle.com");

Thanks.

The best way is to not use an XML parser. XML parsers are required to throw an exception and stop parsing as soon as they encounter malformed XML.

And since (according to your example) you're trying to parse HTML, you would be better off to use an HTML parser that produces a DOM.

Thanks.

I used the html parser (http://htmlparser.sourceforge.net/) and it works fine.