# Finding Divisors and adding them up to find Perfect numbers - Program

**807596**Jan 6, 2005 4:16 PM

I need my program to be able to find the first 4 perfect numbers. It is a perfect number if all of its divisors add up to the number. So 6 is the first one (1+2+3=6)

My program compiles, but when it runs it doesnt do anything. It must be getting stuck in one of my while loops or something. I cannot spot where the code is wrong but can anyone else see it?

My program compiles, but when it runs it doesnt do anything. It must be getting stuck in one of my while loops or something. I cannot spot where the code is wrong but can anyone else see it?

```
import java.io.*;
public class Proj05b
{
public static void main (String[] args) throws IOException
{
int testnumber = 2; //the testing number
int testdivisor = 1; //the test divisor
int divisors; //the amount of divisors
int divisor1 = 0; //the value of 1st divisor
int divisor2 = 0; //2nd divisor
int divisor3 = 0; //3rd divisor
int divisor4 = 0; //4th divisor
int hits2 = 0;
int hits = 0; //# Of hits the last if statement has,
//once it reaches 4 it ends program
while (hits < 4)
{
testnumber++; //Testing the next number
testdivisor = 1; //Resetting the testdivisor
hits2 = 0;
while (hits2 == 0) //Making sure testdivisor isn't
{ //over half the number, needless
while (testdivisor <= testnumber)
{
divisors = (testnumber % testdivisor);
if (divisors==0)
{
if (divisor1==0)
{
divisor1=testdivisor;
}
else if (divisor2==0)
{
divisor2=testdivisor;
}
else if (divisor3==0)
{
divisor3=testdivisor;
}
else if (divisor4==0)
{
divisor4=testdivisor;
}
}
if ((divisor1+divisor2+divisor3+divisor4)==testnumber)
{
System.out.println(testnumber);
hits2++;
hits++;
}
else if ((divisor1+divisor2+divisor3+divisor4)!=testnumber)
{
testdivisor++;
}
}
}
}
}
}
```

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