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Xalan Help

843834Jun 12 2005 — edited Aug 30 2005

Dear All:

Hi, anyone have idea XSLTInputSource in xalan_1_0_0 is replace by what under xalan-j_2_6_0? or anyone can please guide me how to input stylesheet (which is in Document object) . Thanks

:~)

843834

I don't use Xalan explicitly, but I'd imagine the newer versions support the Source interface <http://java.sun.com/j2se/1.5.0/docs/api/javax/xml/transform/Source.html> so you'd want one of DOMSource, SAXSource, StreamSource. DOMSource if it's in a DOM Document.

Pete

843834

hi all:

i am totally new to xalan. in xalan 1_0_0, XSLTInputsource can take in the input xsl file as a document like this:

XSLTInputSource xmlIn = new XSLTInputSource(xmlDoc);
XSLTInputSource xslIn = new XSLTInputSource(xslDoc);

XSLTProcessor processor = XSLTProcessorFactory.getProcessor();
processor.process(xmlIn, xslIn, xmlOut);
baos.close();
String result = baos.toString();

the first line is taking another xml file and the second line is taking the xsl file.
i ffind the DOMSource, but there seem no method support taking in document, can anyone please help, i am not familiar in java and also xalan

Thanks for helping

843834

The DOMSource constructor takes a Node argument; Document is a subtype of Node:

    final ByteArrayOutputStream baos = new ByteArrayOutputStream();

    final Source xmlIn = new DOMSource(xmlDoc);
    final Source xslIn = new DOMSource(xslDoc);
    final Result xmlOut = new StreamResult(baos);
    
    final TransformerFactory transformerFactory = TransformerFactory.newInstance();
    final Transformer transformer = transformerFactory.newTransformer(xslIn);
    
    transformer.transform(xmlIn, xmlOut);
    
    baos.close();
    String result = baos.toString("UTF-8");

843834

Hi:

first of all, thanks for your code and help.
but how come i got this error?

javax.xml.transform.TransformerConfigurationException: javax.xml.transform.Trans
formerException: javax.xml.transform.TransformerException: stylesheet requires attribute: version

thanks

843834

The root element in your XSL file needs to contain a verison number:

<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <!-- your code goes here -->
</xsl:stylesheet>

Cheers, Neil

843834

Hi:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output version="1.0" indent="yes" encoding="UTF-8" omit-xml-declaration="no" method="xml"/>

this is my xsl heading, but i still got the same error message

Thank You

843834

A quick google might shed some clues?

http://www.google.co.uk/search?q=stylesheet+requires+attribute%3A+version

Could be something to do with the parser / transformer implementation?

Cheers, Neil

843834

hi:

i have try to find in google, but i cant find any solution. :(

public static Document transformXML(Document xmlDoc, Document xslDoc){

ByteArrayOutputStream baos = new ByteArrayOutputStream();
Source xmlIn = new DOMSource(xmlDoc);
Source xslIn = new DOMSource(xslDoc);
Result xmlOut = new StreamResult(baos);

TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer(xslIn);
transformer.transform(xmlIn, xmlOut);

baos.close();

String result = baos.toString("UTF-8");
}

this is my java code and my xsl heading is:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="xml"
doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"/>

but still always give me this exception:
****************************************************************************************
javax.xml.transform.TransformerConfigurationException: javax.xml.transform.Trans
formerException: javax.xml.transform.TransformerException: stylesheet requires a
ttribute: version
***************************************************************************************

anyone know how to solve? please help!!.

Thanks

843834

I would suggest printing out the full path of your XSLT file just before the exception is thrown. Perhaps your application is attempting to read an old file without the correct attributes?

Also, perhaps you could post the stacktrace, wrapped in [ code ] blocks, and then show the associated line numbers from your code.

If you are using an IDE, then perhaps you could add a breakpoint just before the exception is thrown, and check all variables contain the correct information?

Cheers, Neil

843834

Hi:

thanks for your reply, did you mean i print the whole string out?

sorry, i don't really understand....i am a newbie to java and XSL also...

can elaborate more?

Thanks

843834

hi:

has anyone really try the transform and can successfully got the result?

i try with another code:

File xmlFile = new File("C:/a.xml");
File xsltFile = new File("C:/b.xsl");

Source xmlSource = new StreamSource(xmlFile);
Source xsltSource = new StreamSource(xsltFile);

TransformerFactory transFact =
TransformerFactory.newInstance();
Transformer trans = transFact.newTransformer(xsltSource);

trans.transform(xmlSource, new StreamResult(System.out));

for this case, it does not give me that exception, (I also no idea why)
but it only print out this:

<?xml version="1.0" encoding="UTF-8"?>
then it stop..

anyone have other way to do transformation using xsl...please help...:'(

Thank You

843834

Try the following.
TraxTester class:

import java.io.InputStream;

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class TraxTester {

	public static void main(String[] args) throws Exception {
		// for this example, files are in the same directory as this class
		InputStream ixml = TraxTester.class.getResourceAsStream("test.xml");
		InputStream ixsl = TraxTester.class.getResourceAsStream("test.xsl");
		
		StreamSource xml = new StreamSource(ixml);
		StreamSource xsl = new StreamSource(ixsl);
		StreamResult out = new StreamResult(System.out);
		
		TransformerFactory factory = TransformerFactory.newInstance();
		Transformer transformer = factory.newTransformer(xsl);
		
		// print out implementing classes for reference
		System.out.println("TransformerFactory: "+factory.getClass().getName());
		System.out.println("Transformer: "+transformer.getClass().getName());
				
		transformer.transform(xml, out);
	}

}

test.xml:

<root>
	<line>Hello</line>
	<line>World</line>
</root>

test.xsl:

<xsl:stylesheet 
	version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	
	<xsl:output method="html"/>

	<xsl:template match="root">
		<html>
			<head></head>
			<body>
				<xsl:apply-templates/>				
			</body>
		</html>

	</xsl:template>
	
	<xsl:template match="line">
		<xsl:value-of select="."/><br/>
	</xsl:template>
	
</xsl:stylesheet>

What classes are reported for TransformerFactory and Transformer?
Cheers, Neil

843834

hi neil:

I am transforming xhtml to xml, not xml to html, so the xsl heading, do i still need to change the html?

and i try the code and i got these error:

Exception in thread "main" javax.xml.transform.TransformerConfigurationException
: javax.xml.transform.TransformerConfigurationException: javax.xml.transform.Tra
nsformerException: java.lang.NullPointerException
at org.apache.xalan.processor.TransformerFactoryImpl.newTransformer(Tran
sformerFactoryImpl.java:805)
at TraxTester.main(TraxTester.java:20)
Caused by: javax.xml.transform.TransformerConfigurationException: javax.xml.tran
sform.TransformerException: java.lang.NullPointerException
at org.apache.xalan.processor.TransformerFactoryImpl.newTemplates(Transf
ormerFactoryImpl.java:984)
at org.apache.xalan.processor.TransformerFactoryImpl.newTransformer(Tran
sformerFactoryImpl.java:788)
... 1 more
Caused by: javax.xml.transform.TransformerException: java.lang.NullPointerExcept
ion
at org.apache.xalan.processor.TransformerFactoryImpl.newTemplates(Transf
ormerFactoryImpl.java:980)
... 2 more
Caused by: java.lang.NullPointerException
at org.apache.crimson.parser.Parser2.parseInternal(Parser2.java:691)
at org.apache.crimson.parser.Parser2.parse(Parser2.java:337)
at org.apache.crimson.parser.XMLReaderImpl.parse(XMLReaderImpl.java:448)

at org.apache.xalan.processor.TransformerFactoryImpl.newTemplates(Transf
ormerFactoryImpl.java:972)......
......

is it that transformation is only use to convert xml to html?

my xsl file is like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/html/body/table[5]/tr/td/table/tr[3]/td/table/tr/td[2]/table">
<Username>
<xsl:value-of select="tr[2]/td[2]/b"/>
</Username>
<Address>
<xsl:value-of select="tr[3]/td[2]/b"/>
</Address>
</xsl:template>

Thanks for your help!!

:~ )

843834

I would suggest creating a small test program, with a simple XML and XSLT file, then slowly add more steps until you uncover your error.

From your stacktrace, it appears that you may be attempting to create a transformer where the StreamSource is null.

Cheers, Neil

843834

Check my blog entry:
http://photeus.com:8080/roller/page/gary_kephart/20050829#transformerexception_stylesheet_requires_attribute_version

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