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APEX 5.1.1 IG - how to set value of a hidden column

Marko GorickiApr 12 2017 — edited Oct 13 2017

Hi,

can anybody give me a clue how to set value of a hidden column in Interactive Grid.

I have a sample here.

There's a button "Set salary to 1000 of selected emp" on this page that executes the following JS code:

var g = apex.region('rgnEmp').widget().interactiveGrid('getViews','grid');
var r = g.getSelectedRecords()[0];
g.model.setValue(r, 'SAL', 1000);

https://apex.oracle.com/pls/apex/f?p=103570:4:Column SAL is defined as hidden and not protected.

The error that I see in console is:

Uncaught Error: Set value not allowed for field.

Tested on apex.oracle.com (version5.1.1.00.08).

Thanks in advance!

Br,

Marko

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Post Details

Locked on Nov 10 2017
Added on Apr 12 2017
#apex-discussions, #interactive-grid
11 comments
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