Hi
I tried to install 19c EE on Windows 2012R2 with several options (Virtual account, Administrator) and the problem remains the same :
After choosen the default Oracle base directory C:\app\Administrator, some directories (as network) are not copied in it by only updated in the installation directory (where the dezipp file was located : C:\temp\ora19). Example : no C:\app\Administrator\product\19......\dbhome_1 is created. After installation :
PATH=C:\temp\ora19\bin;C:\Users\Administrator\Downloads\oracle19\bin;C:\Windows\system32;C:\Windows;C:\Windows\System32\Wbem;C:\Windows\System32\WindowsPowerShell\v1.0\
The same problem appears with 18c EE, where the installation directory take place for several directories on the oracle home directory choosen at the installation time. See 1, 2 and 3.jpg files.
An article quotes in spanish
"Desde Oracle 18c, el proceso de instalación ha sido simplificado, y el nuevo proceso no copia los archivos desde un directorio de instalación al nuevo ORACLE_HOME sino que simplemente registra y configura los componentes del producto."
but the doc talk to dezipp the installation file in a separate directory (ex : mkdir \install\database)
An explanation is given in
https://blog.toadworld.com/2018/09/26/how-to-install-oracle-database-18c-on-windows
To proceed to the next step, we need to extract the content of file, but before doing that it’s very important to know that with Oracle 11g or 12c we were allowed to set the location of our db_home directory, but starting with Oracle Database 18c we are introduced to a new concept: Image Based Installation. In Image Based Installation the Oracle Universal Installer of 18c takes the location of our setup.exe file and assigns it as its db_home location. That’s why before we start extracting the content of this file, we first need to decide where we want to create our db_home directory.
Why this point is not indicated in the official documentation?