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regexp_substr

465486Oct 26 2007 — edited Oct 29 2007
Hello Gurus

I'm trying to extract 10999 from the string bellow with regexp, but

select regexp_substr('Fast10999/2/3/4','[0-9]+/') from dual

returns "10999/". How can I say something like return me the string of digits BEFORE the first slash?

Thank you all very much,

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Locked on Nov 26 2007
Added on Oct 26 2007
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