9 Replies Latest reply: Sep 4, 2008 10:59 AM by JonWat

# range query

I have a table:

CREATE TABLE TEST
(
name VARCHAR2(10 BYTE),
num NUMBER
)

select * from test order by num;
name, num
A, 1 *
B, 4
C, 8
D, 18 *
h, 21
E, 34 *
f, 35
t, 36
L, 51 *
Z, 55

I need a query to get records where the num value >= previous got num value + 15
(the records to find are marked with *)
The first record is always valid.
In the example above, I don't get record (C, 8) because the difference with num value of record (A,1) is less then 15,
but i get record (L, 51) because the difference with num value of record (E,34) is more then 15.

thanks
• ###### 1. Re: range query
How do you detrmine which row to compare with.
Its clearly not the previous row judging by your example.

Here's a pointer. (Analytics )
``````with testdata as
(
select 'A' name, 1 num from dual union all
select 'B', 4 from dual union all
select 'C', 8 from dual union all
select 'D', 18  from dual union all
select 'h', 21 from dual union all
select 'E', 34  from dual union all
select 'f', 35 from dual union all
select 't', 36 from dual union all
select 'L', 51  from dual union all
select 'Z', 55 from dual
)
select name,num
from
(
select name,num,lag(num,1,0) over (partition by 1 order by 1) prev_num from testdata
order by num
)
where num >= (prev_num+15)``````
• ###### 2. Re: range query
To phrase it differently, don't you just want the lowest number in each "bucket" of 15?
``````select num
from (select trunc(num/15), min(num)
from test
group by trunc(num/15)
)``````
• ###### 3. Re: range query
``````SQL&gt; edit

Wrote file sqlplus_buffer.sql

1  WITH test AS

2  (

3     SELECT 'A' AS name, 1 AS num FROM DUAL UNION ALL

4     SELECT 'B' AS name, 4 AS num FROM DUAL UNION ALL

5     SELECT 'C' AS name, 8 AS num FROM DUAL UNION ALL

6     SELECT 'D' AS name, 18 AS num FROM DUAL UNION ALL

7     SELECT 'h' AS name, 21 AS num FROM DUAL UNION ALL

8     SELECT 'E' AS name, 34 AS num FROM DUAL UNION ALL

9     SELECT 'f' AS name, 35 AS num FROM DUAL UNION ALL

10     SELECT 't' AS name, 36 AS num FROM DUAL UNION ALL

11     SELECT 'L' AS name, 51 AS num FROM DUAL UNION ALL

12     SELECT 'Z' AS name, 55 AS num FROM DUAL

13  )

14  SELECT a.name,a.num,a.diff

15  FROM

16  (SELECT name,num,num-(LAG(num,1) OVER (order by num)) AS diff FROM test order by num) a

17* WHERE a.diff &gt;= 15 OR a.diff IS NULL

SQL&gt; /

N        NUM       DIFF

- ---------- ----------

A          1

L         51         15

SQL&gt;``````
I hope this helps. I had a hard time understanding your requirements.
• ###### 4. Re: range query
Thanks, but the solution is not correct.
Sorry, but the problem is very difficult to explain.

the range(15) start from the first record, so if the first number is 14, the second number will be >= 30.
Other example:

A, 14
B, 15
C, 19
D, 29
E, 30
F, 50
G, 51

I want select only 3 records: (A,14) , (E, 30) , (F, 50)

I hope that this example is more clearly.
• ###### 5. Re: range query
Why is the second number 30 and not 29?

According to the original post, it must be >= the previously selected number + 15.

14+15 = 29.

There's an entry for 29, so the second record should be that one.

Assuming I'm right, you just need to "adjust" your window by the 1st value.
``````with test as (
select 'A' nam,  14 num from dual union all
select 'B',  15 from dual union all
select 'C',  19 from dual union all
select 'D',  29 from dual union all
select 'E',  30 from dual union all
select 'F',  50 from dual union all
select 'G',  51 from dual)
select num
from (select trunc((num-minnum)/15), min(num) num
from test, (select min(num) minnum from test) x
group by trunc((num-minnum)/15)
)

NU
--
14
29
50``````
• ###### 6. Re: range query
Ah I got you now

Always choose first number
Second number is first number that is 15 greater than first number
3rd number is first number that is 15 greater than second number.
etc

which gives
A, 14
E, 30
F, 50
• ###### 7. Re: range query
I solved same question :-)
Select records at interval of 5 minutes

and my site mentions same question B-)
http://www.geocities.jp/oraclesqlpuzzle/10-245.html
• ###### 8. Re: range query
thanks, very good, very well ...

I have an other question ....
I have the same scenario but more complicated, I have 3 columns: surname, name, datatime
and I have to use the same reasoning but for each surname:
example:
the range is 15 minuts

surname, name, datatime (dd/mm/yyyy hh24.mi)
x, a, 03/09/2008 10.00
x, b, 03/09/2008 10.08
x, c, 03/09/2008 10.16
y, a, 03/09/2008 10.10
y, b, 03/09/2008 10.30
y, c, 03/09/2008 10.50

i want select 5 record:
(x, a, 03/09/2008 10.00), (x, c, 03/09/2008 10.16) , (y, a, 03/09/2008 10.10) , (y, b, 03/09/2008 10.30) ,
(y, c, 03/09/2008 10.50)

thanks
• ###### 9. Re: range query
I don't think that is the correct answer. I think that will only work if you always manage to stay at the bottom boundary of your window (e.g. 14, 29, 44, 59 etc.)

It fails with the following data (gives you 40 and 45).

Aketi Jyuuzu's method works. Method is to work out what the next row would be if any given row is chosen (i.e. the first row that is at least 15 away), and then use a hierarchical query to choose the rows you would actually need starting with whatever is your first row.

(actually need to create a table so you can use rowids)

create table testxx as (
select 'A' nam, 14 num from dual union all
select 'B', 15 from dual union all
select 'C', 19 from dual union all
select 'D', 40 from dual union all
select 'E', 41 from dual union all
select 'F', 45 from dual union all
select 'G', 56 from dual);

with WorkView as (
Select nam,num,RowID as Row_ID,min(num) over() as startnum,
first_value(RowID) over(order by num
range between 15 following
and unbounded following) as childRowID
from Testxx)
select nam,num
from WorkView