Count positive values and compare with total count to get the aggregated share of positive values

Question

Summary:

How can I count the number of positive values in a column and compare with the total count to get the share percentage of positive values?

Content (required):

I have column with positive, negative and 0 values. I want to count the number of positive values (>0) and then compare with the count of all values to show which percentage of the values are positive on an aggregated level.

Please see screenshot for details.

Thanks in advance!

Version (include the version you are using, if applicable):

22D

Code Snippet (add any code snippets that support your topic, if applicable):

Stefan pettersson · Answer

Thanks Amrita and Venkat!

Appreciate the added info Venkat, very useful! Thanks

Venkat Koduvayur-Oracle · Answer

Hi @Stefan pettersson

You could define the formula as below

No of Positive Values: SUM(CASE WHEN "Facts"."Amount">0 THEN 1 ELSE 0 END)

Count of All Values:  count("Facts"."Amount")

% of Positive Values: (SUM(CASE WHEN "Facts"."Amount">0 THEN 1 ELSE 0 END)/count("Facts"."Amount"))*100

Have used both table view and pivot view to aggregate the data at business unit level.

Pivot view setting

Hope this helps

Regards

Venkat

Amrita Gupta-Oracle · Answer

Hi @Stefan pettersson,

I used the below formulae, and, the have included screenshot of the results as well. Please check if this works for you -

Positives ---- SUM(CASE WHEN <"Fact"."Col"> > 0 THEN 1 ELSE 0 END)

Total ------ COUNT("Fact"."Col")