Still trying to understand swap -l and -s relationship; please advise
Hello,
I think I've already passed by the fundamental swap docs and threads but can you, please, help me again understanding the following swap info from a Solaris 11 (SRU 8.5) box?
I think I've already passed by the fundamental swap docs and threads but can you, please, help me again understanding the following swap info from a Solaris 11 (SRU 8.5) box?
$ swap -lh; swap -shThe question is:
swapfile dev swaplo blocks free
/dev/zvol/dsk/rpool/swap 195,2 4K 8.0G 8.0G
total: 4.6G allocated + 420M reserved = 5.0G used, 7.1G available
If disk-based swap is practically unused, with 5 GB used (4.6 GB allocated) and 7.1 GB is generally available, then is this available and used swap coming mostly from RAM?
But isn't that the case that swap usage begins by disk instead of RAM?
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