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How to return array in fast formula

edited Sep 5, 2020 12:10AM in Benefits 9 comments

Summary

How to return array in fast formula

Content

I have a requirement to route the approval to a particular role when a Compensation plan is submitted. For example, when a manager has submitted a compensation plan for approval, it should route to all the users assigned to a particular role. I tried achieving it using fast formula but could not successfully do it. Can anyone suggest me how to achieve this.

My Formula:

DEFAULT_DATA_VALUE FOR PER_EXT_PER_USER_ID IS 0
L_PERSON_NUMBER= ' '
I=1

WHILE PER_EXT_PER_USER_ID.EXISTS(I) LOOP

(
l_user_id=to_char(PER_EXT_PER_USER_ID[I])

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