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how to create hyperlink field in oracle cx mobile application.

in Sales 1 comment

Hi Team,

We are trying to expose hyperlink field in mobile cx application. To achieve this requirement , we have created text formula field in respective object and exposed in mobile application setup. But in mobile it is coming as url link instead of hyperlink.

below is the sample code of the same:-

def vo = newView('Resource')
def vc = newViewCriteria(vo)
def vcr = vc.createRow()
def vci1 = vcr.ensureCriteriaItem('PartyId')
vci1.setOperator('=')
vci1.setValue(adf.util.getUserPartyId())
vc.insertRow(vcr)
vo.appendViewCriteria(vc)
vo.executeQuery()
if (vo != null) {
if(vo.hasNext())
{
def found = vo.next();
def flag = found?.FB_BranchOffice_Obj_c?.RecordName

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